20y^2-19y-28=0

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Solution for 20y^2-19y-28=0 equation:


Simplifying
20y2 + -19y + -28 = 0

Reorder the terms:
-28 + -19y + 20y2 = 0

Solving
-28 + -19y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-4 + -5y)(7 + -4y) = 0

Subproblem 1

Set the factor '(-4 + -5y)' equal to zero and attempt to solve: Simplifying -4 + -5y = 0 Solving -4 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -5y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -5y = 0 + 4 -5y = 0 + 4 Combine like terms: 0 + 4 = 4 -5y = 4 Divide each side by '-5'. y = -0.8 Simplifying y = -0.8

Subproblem 2

Set the factor '(7 + -4y)' equal to zero and attempt to solve: Simplifying 7 + -4y = 0 Solving 7 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -4y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -4y = 0 + -7 -4y = 0 + -7 Combine like terms: 0 + -7 = -7 -4y = -7 Divide each side by '-4'. y = 1.75 Simplifying y = 1.75

Solution

y = {-0.8, 1.75}

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